-0.1x^2+20.1x-854=0

Solution for -0.1x^2+20.1x-854=0 equation:

-0.1x^2+20.1x-854=0

a = -0.1; b = 20.1; c = -854;
Δ = b2-4ac
Δ = 20.12-4·(-0.1)·(-854)
Δ = 62.41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20.1)-\sqrt{62.41}}{2*-0.1}=\frac{-20.1-\sqrt{62.41}}{-0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20.1)+\sqrt{62.41}}{2*-0.1}=\frac{-20.1+\sqrt{62.41}}{-0.2}
$